How to control amps of IOUT with mA of IC using legacy voltage regulators as current regulators where IOUT = (VADJ - ICRC)/RS

AuthorsStephen Woodward
Main DocumentArticle «Cross connect complementary current sources to reduce self-heating error»
DescriptionFigure 1
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How to control amps of I sub OUT /sub  with mA of I sub C /sub  using legacy voltage regulators as current regulators where I sub OUT /sub  = (V sub ADJ /sub  - I sub C /sub R sub C /sub )/R sub S /sub

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