.. however, IC1’s “-” pin will be near ground when the voltage across R1 is less than 1.24 V, and about a volt below V+ when the voltage across R1 is greater than 1.24 V. Figure 1. This low-cost, space-saving circuit will ...
.. imposes a self-discharge current of less than 1 mA, which represents a capacitor-battery discharge rate of 5000 sec per volt into an open circuit. You can reduce the LP2996's self-discharge current by applying an external control ...
.. resets through R 3 and D 3 . The voltage at T 1 ’s secondary winding goes slightly negative to balance the core's volt-second characteristic, which forward-biases Q 3 ’s body diode without current, and Q 4 ’s body diode ...
.. but it unconditionally starts at a very low voltage. Previous silicon-transistor boost circuits required approximately a volt to start and many more components. Figure 1. This open-loop boost circuit starts with as little as 260-mV input ...
.. shown in Figure 1 enables an amplifier that can deliver higher output voltage swings while still using standard (e.g., 15-volt) op amps at the front end. Figure 1. Schematic of high output voltage swing current booster. Higher swing is ...
.. near the center of its 0 to 2.5 V range provides the best linearity. Figure 1. Clamp circuit to precision clamp a 2.5 Volt output while operating on a 2.5 Volt power supply. To achieve this, the reference voltage is halved via the ...
.. C FLY , a second inductor L2, a catch diode D4, and the negative output capacitor C O2 . According to the inductor volt-second balance for the circuit loop of C O1 -L1-C FLY -L2, the average voltage across L1 and L2 is zero, so the ...
.. effective the voltage drop across the source resistor must be comparable to the threshold, making it a large fraction of a volt. The consequence is that the equalizing resistors dissipate large power, and the voltage drop across them eats ...
.. clockwise. On Range C, an external voltage source that connects to R 13 controls the load current at a rate of 1 A per volt with P 1 set fully clockwise. You can drive the external input with a function generator to test a power ...
.. of 63 V means that the required caps are both big and expensive. A second approach would be to increase the LT8362 output a volt or two and add an LDO regulator to the output. This requires a high voltage LDO regulator, which usually costs ...